2b^2-4b+17=2

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Solution for 2b^2-4b+17=2 equation:


Simplifying
2b2 + -4b + 17 = 2

Reorder the terms:
17 + -4b + 2b2 = 2

Solving
17 + -4b + 2b2 = 2

Solving for variable 'b'.

Reorder the terms:
17 + -2 + -4b + 2b2 = 2 + -2

Combine like terms: 17 + -2 = 15
15 + -4b + 2b2 = 2 + -2

Combine like terms: 2 + -2 = 0
15 + -4b + 2b2 = 0

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
7.5 + -2b + b2 = 0

Move the constant term to the right:

Add '-7.5' to each side of the equation.
7.5 + -2b + -7.5 + b2 = 0 + -7.5

Reorder the terms:
7.5 + -7.5 + -2b + b2 = 0 + -7.5

Combine like terms: 7.5 + -7.5 = 0.0
0.0 + -2b + b2 = 0 + -7.5
-2b + b2 = 0 + -7.5

Combine like terms: 0 + -7.5 = -7.5
-2b + b2 = -7.5

The b term is -2b.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2b + 1 + b2 = -7.5 + 1

Reorder the terms:
1 + -2b + b2 = -7.5 + 1

Combine like terms: -7.5 + 1 = -6.5
1 + -2b + b2 = -6.5

Factor a perfect square on the left side:
(b + -1)(b + -1) = -6.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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